Answer:
t=3.673900
Explanation:
Given
df = 28df=28 -- degree of freedom
Area = 0.005Area=0.005
Required
Determine the t-value
The given parameters can be illustrated as follows:
P(T > t) = \alphaP(T>t)=α
Where
\alpha = 0.005α=0.005
So, we have:
P(T > t) = 0.005P(T>t)=0.005
To solve further, we make use of the attached the student's t distribution table.
From the attached table,
The t-value is given at the row with df = 28 and \alpha = 0.005α=0.005 is 3.673900
Hence, t = 3.673900t=3.673900
