[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]
[tex] \huge \boxed{\mathfrak{Answer} \downarrow}[/tex]
[tex] \sf\frac { p } { 3 } \lt - 6 \\ [/tex]
Multiply both sides by 3. As 3 is >0, the inequality direction remains the same.
[tex] \sf \: p<-6\times 3 [/tex]
Multiply -6 and 3 to get -18.
[tex] \boxed{ \boxed{ \bf \: p<-18 }}[/tex]
