[tex]sec^{2}x[/tex]·[tex]cotx-cotx = tanx[/tex]

I'm supposed to prove this but don't know how? Can someone help, please!

Question

02-02-2021
Mathematics

contestada

[tex]sec^{2}x[/tex]·[tex]cotx-cotx = tanx[/tex]

I'm supposed to prove this but don't know how? Can someone help, please!

Respuesta :

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DWRead DWRead · Answer 1 · 2021-02-02T02:29:02+01:00

DWRead DWRead

02-02-2021

sec²(x)cot(x) - cot(x) = (1/cos²(x))(cos(x)/sin(x)) - cos(x)/sin(x)
= (1/cos(x))(1/sin(x)) - cos(x)/sin(x)
= (1/cos(x))(1/sin(x)) - cos²(x)/( cos(x)sin(x))
= (1-cos²(x))/(cos(x)sin(x))
= sin²(x)/(cos(x)sin(x))
= sin(x)/cos(x)
= tan(x)

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[tex]sec^{2}x[/tex]·[tex]cotx-cotx = tanx[/tex] I'm supposed to prove this but don't know how? Can someone help, please!

Respuesta :

Otras preguntas

[tex]sec^{2}x[/tex]·[tex]cotx-cotx = tanx[/tex]

I'm supposed to prove this but don't know how? Can someone help, please!