katiemaew1
katiemaew1 katiemaew1
  • 03-12-2020
  • Mathematics
contestada

please help me, i don’t know how to do this:)

please help me i dont know how to do this class=

Respuesta :

NAWty12345
NAWty12345 NAWty12345
  • 03-12-2020

x=12, y=[tex]6\sqrt{2}[/tex]

This triangle is a special right triangle, a 45-45-90 triangle. In this format, the the hypotenuse will be [tex]x\sqrt{2}[/tex], while the side lengths would be x. With this in mind we can already figure out y is [tex]6\sqrt{2}[/tex]. The hypotenuse would be [tex](6\sqrt{2} )(\sqrt{2} )=12[/tex]

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