mmcdowell mmcdowell
  • 11-09-2016
  • Mathematics
contestada

How do you solve this problem for x?
2^x = 5

Respuesta :

gabriel24111999
gabriel24111999 gabriel24111999
  • 14-09-2016
       2^x = 5
-> log2^x = log5
-> xlog2 = log5
-> x = log5/log2
-> x = 2.322

The approximate answer is 2.322
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