Thedakfiqjd Thedakfiqjd
  • 03-01-2020
  • Mathematics
contestada

PLEASE ANSWER; MAY NOT BE HARD

Find the sum of all positive 3-digit numbers whose last digit is 2

Respuesta :

surjithayer10otahza surjithayer10otahza
  • 04-01-2020

Answer:

Step-by-step explanation:

 102+202+302+402+502+602+702+802+902(4518)

+112+212+312+...+ 812+912(4608)

+122+222+322+...+822+922(4698)

+132+232+332+...+932(4788)

..........................................

+192+292+392+...+992(5328)

4518+4608+4698+...+5328

n=10

[tex]s=\frac{10}{2}(4518+5328)\\=5(9846)\\=49230[/tex]

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