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  • 02-03-2019
  • Mathematics
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lastbenchstudent
lastbenchstudent lastbenchstudent
  • 02-03-2019

[tex]2 {sin}^{2} x = sin \: x \\ 2 {sin}^{2} x - sin \: x = 0 \\ sin \: x \: (2 sinx - 1) = 0 \\ \\ now \: sin \: x \: = 0 \\ x \: = \: 0 \: or \: \pi \: or \: 2\pi \\ \\ from \: 2nd \: factor \\ 2sin \: x \: - 1 = 0 \\ sin \: x \: = \frac{1}{2} \\ x \: = \frac{\pi}{6} [/tex]

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