brandonkestler7 brandonkestler7
  • 03-11-2018
  • Mathematics
contestada

write the equation in vertex form for the quadratic function with vertex (-6,4) and passing through point (-2,12).show your work

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jimrgrant1 jimrgrant1
  • 03-11-2018

y = [tex]\frac{1}{2}[/tex](x + 6)² + 4

the equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

here (h, k ) = (- 6, 4 ), hence

y = a(x + 6 )² + 4

To find a substitute (- 2, 12) into the equation

12 = 16a + 4 ( subtract 4 from both sides )

8 = 16a ( divide both sides by 16 )

a = [tex]\frac{8}{16}[/tex] = [tex]\frac{1}{2}[/tex]

y = [tex]\frac{1}{2}[/tex](x + 6 )² + 4 ← in vertex form


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