dkoos3369 dkoos3369
  • 02-07-2018
  • Mathematics
contestada

Solve the given initial-value problem. dy dx = x + 2y, y(0) = 7

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LammettHash
LammettHash LammettHash
  • 09-07-2018
[tex]\dfrac{\mathrm dy}{\mathrm dx}=x+2y[/tex]
[tex]\dfrac{\mathrm dy}{\mathrm dx}-2y=x[/tex]
[tex]e^{-2x}\dfrac{\mathrm dy}{\mathrm dx}-2e^{-2x}y=xe^{-2x}[/tex]
[tex]\dfrac{\mathrm d}{\mathrm dx}[e^{-2x}y]=xe^{-2x}[/tex]
[tex]e^{-2x}y=\displaystyle\int xe^{-2x}\,\mathrm dx[/tex]
[tex]e^{-2x}y=-\dfrac14e^{-2x}(1+2x)+C[/tex]
[tex]y=-\dfrac{1+2x}4+Ce^{2x}[/tex]

[tex]y(0)=7[/tex]
[tex]7=-\dfrac{1+2\cdot0}4+Ce^{2\cdot0}[/tex]
[tex]7=-\dfrac14+C[/tex]
[tex]C=\dfrac{29}4[/tex]

[tex]y=-\dfrac{1+2x}4+\dfrac{29}4e^{2x}[/tex]
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