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03-11-2022
Mathematics

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the function h(x)=x^2+5 maps the domain given by the set {-2,-1,0,1,2} determine the set that represents the range of h (x)

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BreysonH245391 BreysonH245391

03-11-2022

h(x) = x^2 + 5

h(-2) = (-2)^2 + 5 = 4 + 5 = 9

h(-1) = (-1)^2 + 5 = 1 + 5 = 6

h(0) = (0)^2 + 5 = 5

h(1) = (1)^2 + 5 = 1 + 5 = 6

h(2) = (2)^2 + 5 = 4 + 5 = 9

The range is {9, 6, 5, 6, 7]

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