From the information given, F(x) = 9.3319419 or approximately 9. This is problem relating to math functions
What is the calculation supporting the above answer?
Recall that we are given x to be = 16.1
Hence,
[tex]f\left(x\right)=\ 2x^{\frac{1}{4}}\ +\ 3x^{\frac{1}{2}}[/tex] =
2 (16.1) ⁰°²⁵ + 3 (16.1)⁰°⁵
= 32.2⁰°²⁵ + 48.3⁰°⁵
= 2.3821218 +6.9498201
f(x) = 9.3319419
f(x) approximately 9
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