4x-9=10x trying to solve for a perimeter of a square

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02-11-2016
Mathematics

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4x-9=10x trying to solve for a perimeter of a square

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nk102777 nk102777 · Answer 1 · 2016-11-02T02:11:06+01:00

nk102777 nk102777

02-11-2016

The perimeter of a rectangle is equal to the sum of all sides of the rectangle.P=L+L+W+W=2L+2WP=L+L+W+W=2⁢L+2⁢WSubstitute the values of the length L=10xL=10⁢x and width W=(4x−9)W=4⁢x-9 into the formula for the perimeter of a rectangle.P=2⋅(10x)+2⋅(4x−9)P=2⋅10⁢x+2⋅4⁢x-9Simplify each term.
P=20x+(8x−18)P=20⁢x+8⁢x-18Simplify by adding terms.
P=28x−18

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