cblack4real
cblack4real cblack4real
  • 01-11-2020
  • Mathematics
contestada

If the equation y² - (K-
2y + 2k +1 = 0
with equal roots find the value of k​

Respuesta :

Lightning25346
Lightning25346 Lightning25346
  • 01-11-2020

Answer:

y² - (K-  2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

Answer Link

Otras preguntas

what wiped out 90% of living coral in the 1970’s
To get an electrical current you have to have a ___ ____.
The three most used means of transportation in Brazil are: trains, roads, and water. True False
The equation of a circle in general form is ​ x²+y²+22x+14y−55=0 ​ . What is the equation of the circle in standard form? A. (x+11)²+(y+7)²=225 B. (x+22)²
what is the midpoint of the segment shown below? (2,3) (10,3)
A government conducting a cost-benefit analysis must consider​
How does Shakespeare use foreshadowing in Macbeth
What was the role of a pope in the Catholic church?A. a person who supervises a number of local churches or a diocese. B. a high ecclesiastic appointed by the p
What is The location of China by stating the two closest lines of latitude along its northern and southern borders; the location of Taiwan by estimating its lat
Millions of dollars have been appropriated by Congresseach year for "Indian Education." All you have to do isencourage your school to use these resources. My In