Answer:
Value of x1 = 10 and x2 = -3
Step-by-step explanation:
[tex]when \: we \: multiply \: the \: above \: matrices \\ we \: get \\ 2x1 + 6x2 = 2 \: \: \: \: and \\ 0x1 + 1x2 = - 3 \\ then \: \: x2 = - 3 \\ on \: substituting \: x2 = - 3 \:\\ in \: first \: equation \: \\ 2x1 + 6( - 3) = 2 \\ 2x1 - 18 = 2 \\ 2x1 = 20 \\ x1 = \frac{20}{2} \\ x1 = 10[/tex]
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