ddarko091826 ddarko091826

13-05-2020
Chemistry

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How many grams of beryllium chloride (BeCl2) are needed to make 7.7 L of a 0.69 M solution?

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valeherrera333 valeherrera333

13-05-2020

Answer:

419.5 g BeCl2

Explanation:

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (0.69 M) * (7.7 L)

mol solute=5.31 mol BeCl2

1 mol BeCl2 -> 79 g

5.31 mol BeCl2 -> x x= 419.5 g BeCl2

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