jkplant4792 jkplant4792
  • 16-01-2020
  • Physics
contestada

If the monthly electricity consumption of a household is 6,619 kWh, what is this consumption expressed in kJ

Respuesta :

sebasacevedop
sebasacevedop sebasacevedop
  • 16-01-2020

Answer:

[tex]2.38*10^{4}kJ[/tex]

Explanation:

One watt equals to 1 joule per second. So, one kilowatt equals 1 kilojoule per second. Thus, one kilowatt-hour is equivalent to:

[tex]1kWh=1\frac{kJ}{s}*3600s=3600kJ[/tex]

Finally, we can calculate the monthly electricity consumption in kJ:

[tex]6,619kWh*\frac{3600kJ}{1kWh}=2.38*10^{4}kJ[/tex]

Answer Link

Otras preguntas

What led to the diverse populations of New York and New Jersey?
what did Benjamin franklin feel strong about
Why does more solar energy reach the equatorial regions than the polar regions?
what's the square root of 135
What Should I Know About Nigeria?
How do you use Bill of rights in a sentence
Which statement accurately describes the Battle of Marathon?   A. Athens fought alone against Darius's army and decisively defeated the Pers
Help me please. What Is Stonehenge?
How do you solve p+9 <7 AND graph it???
What is social Darwinism and how was it tied to imperialism?