01-11-2019
Physics

contestada

A 5 kg weight is hung from a vertical spring. The spring stretches by 5 cm. How much mass should be hung from the spring so it will stretch by 10
cm from its original length?
15 kg
25 kg
10 kg
20 kg

Respuesta :

MathPhys MathPhys

01-11-2019

Answer:

10 kg

Explanation:

F = kx

(5 kg) (9.8 m/s²) = k (0.05 m)

k = 980 N/m

F = kx

m (9.8 m/s²) = (980 N/m) (0.10 m)

m = 10 kg

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