Answer:
0.24 mol/L.
Explanation:
- Ca(OH)₂ dissociates in solution according to the equation:
Ca(OH)₂ → Ca²⁺ + 2OH⁻.
Every 1.0 mol of Ca(OH)₂ dissociates to give 2.0 moles of OH⁻.
∴ The no. of moles of OH⁻ produced from 0.06 mol of Ca(OH)₂ = (2 x 0.06 mol) = 0.12 mol.
∴ [OH⁻] = no. of moles / V of the solution = (0.12 mol)/(0.5 L) = 0.24 mol/L.
