charity09
charity09 charity09
  • 02-04-2016
  • Mathematics
contestada

How do I solve for x? log (x-2) = -1 + log (x+1)

Respuesta :

pegah
pegah pegah
  • 02-04-2016
For this question you can say:
log(x-2) - log(x+1) = -1 
and you should know that log(x-2) minus log(x+1) is equal to:
log((x-2)/(x+1)) 
so now you have:
log((x-2)/(x+1)) = -1 
now you can say:
(x-2)/(x+1) = 10^ -1 or (x-2)/(x+1) = 1/10 
now you can say:
10(x-2) = x+1 
10x -20 = x +1 
10x - x = 20+1 
9x = 21 
x = 21/9 
x = 7/3 :)))
I hope this is helpful
have a nice day
Answer Link

Otras preguntas

ok 4/12 is less than 4/6 right ?
Is the exosphere hot or cold
A water sprinkler has a range of 5 meters as shown. The jet of water from the sprinkler sweeps out at an angle of 85° as the nozzle turns. What is the area wate
wich one of these numbers is an rational but not an integer -9 , 0-4.3, 3
let f(x) = x 7 and g(x) = x − 4. find f(x) ⋅ g(x). x2 − 3x − 28 x2 − 3x − 11 x2 3x − 28 x2 3x − 11
How would I write 3 and 2 over 9 as an improper fraction
Question 26 Comparing Powers
11457 rounded to the nearest hundred
Which is a possible way to rewrite the equation y=3x+3b solve for b?
what is 2,789 rouned to the neatest yen